h(x) = 4x+13 per 2x h invers (x) ????????? Help

h(x) = y = (4x + 13)/2x

2xy = 4x + 13
2xy - 4x = 13
x(2y - 4) = 13
x = 13/(2y - 4)

h^-1 (x) = 13/(2x - 4)