Bentuk sederhana dari -3 akar 48 - 4 akar 32 + akar 98 + 11 akar 3

MAPEL = MATEMATIKA
KELAS = 9
BAB = AKAR & PANGKAT

-3√48 - 4√32 + √98 + 11√3
= -3√(16 × 3) - 4√(16 × 2) + √(49 × 2) + 11√3
= -12√3 - 16√2 + 7√2 + 11√3
= -12√3 + 11√3 - 16√2 + 7√2
= -√3 - 9√2

semoga membantu

[tex] - 3 \sqrt{48} - \sqrt{32} + \sqrt{98} + 11 \sqrt{3} \\ = - 3 \sqrt{16 \times 3} - \sqrt{16 \times 2} + \sqrt{49 \times 2} + 11 \sqrt{3} \\ = - 3 \times 4 \sqrt{3} - 4 \sqrt{2} + 7 \sqrt{2} + 11 \sqrt{3} \\ = - 12 \sqrt{3} - 4 \sqrt{2} + 7 \sqrt{2} + 11 \sqrt{3} \\ = - \sqrt{3} + 3 \sqrt{2} [/tex]