Matematika

Pertanyaan

hitunglah jumlah 12 suku pertama deret -3 + (-6) + (-12) + ...!

1 Jawaban

  • a= -3 b=-6-(-3)= -3
    [tex]sn = \frac{n}{2} (a + (n - 1)b)[/tex]
    S12= 12/2 ( -3 + (12-1) -3)
    = 6 (-3 + 11 (-3))
    = 6 (-3 + (-33))
    = 6 (-36)
    = -216

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