diketahui f(x)=x2+3x-1, g(x)=2x+5,dan h(x)=1-x. rumus komposisi fungsi ( g o f o h ) (x)=

f(x) = x² + 3x - 1
h(x) = 1 - x

(foh)(x)
= (1 - x)² + 3(1 - x) - 1
= 1 - 2x + x² + 3 - 3x - 1
= x² - 5x + 3

g(x) = 2x + 5

(gofoh)(x)
= g((foh)(x))
= g(x² - 5x + 3
= 2(x² - 5x + 3) + 5
= 2x² - 10x + 6 + 5
= 2x² - 10x + 11