Tolong dicari bentuk inversnya, lumayan pointnya

Fungsi InveRs

f(x) = y = (x³ + 1)/(x³ + 2)
Kalikan silang
y(x³ + 2) = x³ + 1
x³y + 2y = x³ + 1
x³y - x³ = (1 - 2y)
x³(y - 1) = (1 - 2y)
x³ = (1 - 2y) / (y - 1)
x = ³√((1 - 2y)/(y - 1))

f^-1 (x) = ³√((1 - 2x)/(x - 1))