4x+3y=18 3x+5y=19 tolong carikan jawaban ya pleas

[tex]4x + 3y = 18 \\ 4x = 18 - 3y \\ x = \frac{18 - 3y}{4} \\ [/tex]
substitusikan
[tex]3x + 5y = 19 \\ 3( \frac{18 - 3y}{4} ) + 5y = 19 \\ \frac{54 - 9y}{4} + 5y = 19 \\ \frac{54 - 9y + 20y}{4} = 19 \\ \frac{54 + 11y}{4} = 19 \\ 54 + 11y = 19 \times 4 \\ 54 + 11y = 76 \\ 11y = 76 - 54 \\ 11y = 22 \\ y = 22 \div 11 \\ y = 2[/tex]