Simpangan baku dari data : 2, 3, 4, 5, 6 adalah

jawab

xi = 2,3,4,5,6
n = 5
∑xi = 20
X = 20/5 = 4

s^2 = ∑|xi - X|² /n = 1/5 { (2-4)^2 + (3-4)^2+(4-4)^2 +(5-4)^2 +(6-4)^2}
s^2= 1/5 (4+1+0+1+4) = 1/5 (10) = 2

simpangan baku = s = √s² = √2