Tolong bantu yak soal e dan f
Matematika
trigealelitewarrior
Pertanyaan
Tolong bantu yak soal e dan f
1 Jawaban
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1. Jawaban algebralover
Soal e.
Luas Lingkaran Besar
[tex]L_B= \frac{1}{4}\times \pi \times d^2 \\ \\ L_B= \frac{1}{4}\times \frac{22}{7} \times 56\times56\\ \\ L_B= \frac{1}{4}\times 22 \times 8\times56 \\ \\ L_B= 22 \times 2\times56 \\ \\L_B=9.856\ cm^2 [/tex]
Luas Lingkaran Kecil
[tex]L_K= \frac{1}{4}\times \pi \times d^2 \\ \\ L_K= \frac{1}{4}\times \frac{22}{7} \times 28\times28\\ \\ L_K= \frac{1}{4}\times 22 \times 4\times28 \\ \\ L_K= 22 \times28 \\ \\L_K=616\ cm^2[/tex]
Luas Daerah yang Diarsir
[tex]L=L_B-L_K \\ \\ L=(9.856-616)\ cm^2\\ \\ L=9.240\ cm^2[/tex]
Soal f.
Luas Setengah Lingkaran Besar (d = 84 cm; r = 42 cm)
[tex]L_B= \frac{1}{2}\times \pi \times r^2\\ \\ L_B= \frac{1}{2}\times \frac{22}{7}\times42\times42\\ \\ L_B= \frac{1}{2}\times22\times6\times42\\ \\ L_B= 11\times6\times42 \\ \\ L_B=2.772\ cm^2[/tex]
Luas Setengah Lingkaran Kecil (d = 28 cm; r = 14 cm)
[tex]L_K= \frac{1}{2}\times \pi \times r^2\\ \\ L_K= \frac{1}{2}\times \frac{22}{7}\times14\times14\\ \\ L_K= \frac{1}{2}\times22\times2\times14\\ \\ L_K= 22\times14 \\ \\ L_K=308\ cm^2[/tex]
Luas Daerah yang Diarsir
[tex]L=L_B-L_K \\ \\ L=(2.772-308)\ cm^2\\ \\ L=2.464\ cm^2[/tex]
***Semoga Terbantu***