pesamaan sumbu simetris fungsi kuadrat f(x)=(x-2) (x+6) adalah... minta bantuan nya kak

Fungsi KuaDraT

f(x) = (x - 2)(x + 6)
f(x) = x² + 4x - 12
a = 1
b = 4
c = -12

sumbu simetri = x = -b/2a
x = -4/(2.1)
x = -2