Matematika

Pertanyaan

7 log 49+ 5log625 + 3log81 - 4log32 =....

1 Jawaban

  • 7log49 = 7log7^2 = 2
    5log625 = 5log5^4 = 4
    3log81= 3log3^4 = 4
    4log32 = 4log(4^2x2) = 4log4^2 + 4log2 = 2+1/2 = 2 1/2
    4log2 = 2^2log2^1 = 1/2 

    jadi
    2 + 4 + 4 - 2 1/2 = 10 - 2 1/2 = 7 1/2

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