Tolong jawab dong , Pelajarannya besok makasih semuanya Semoga yang jawab serius dapat pahala

Nomer (1)
f(x) = 2x + 5
g(x) = 4 - 3x
(f o g) (x)
= 2(4 - 3x) + 5
= 8 - 6x + 5
= 13 - 6x

Nomer (2)
f(x) = x - 2
g(x) = x² + 2x - 3
(f o g) (x)
= (x² + 2x - 3) - 2
= x² + 2x - 5

nomer (3)
f(x) = √2x - 6
g(x) = x² - 9
(f o g)(x)
= (√2(x² - 9) - 6)
= √2x² - 18 - 6
= √2x² - 24
= √2 (x² - 12)

Nomer (4)
f(x) = (x - 4) / (1 - 2x)
g(x) = 1/x
(fo g) (x)
= (1/x - 4) / (1 - 2(1/x))
= ( (1 - 4x) / x) / ((x - 2) / x)
= (1 - 4x) / (x - 2)

Nomer (5)
f(x) = (2x + 5) / (x - 1)
g(x) = x - 4
(fo g) (x)
= (2(x - 4) + 5) / (x - 4 - 1)
= (2x - 8 + 5) / (x - 5)
= (2x - 3) / (x - 5)
(fog) (-2)
= (2(-2) - 3) / (-2 - 5)
= -7 / -7
= 1