tolong dibantu ya.....

[tex] ^{3} log( {2x}^{2} - 4x - 12) - ^{3} log(2 + x) = 1 \\ ^{3} log( \frac{{2x}^{2} - 4x - 12}{2 + x} ) = ^{3} log(3) \\ \frac{{2x}^{2} - 4x - 12}{2 + x} = 3 \\ {2x}^{2} - 4x - 12 = 6 + 3x \\ {2x}^{2} - 7x - 18 = 0 \\ [/tex]
x1,2= (7±√(49 -4(2)(-18)) / 4
=( 7±√193)/4

tidak ada jawaban nya di PG. coba dicek lagi apa ada kesalahan dalam perhitungannya