Matematika

Pertanyaan

Nilai limit x ->2 10+5x-5x²_______x²-3x+2=

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  • jawab
    LImit  0/0

    limit ( x-> 2) (10 + 5x - 5x²)/(x² -3x + 2)

    limit (x -> 2) -5(x² - x - 2)/ (x²- 3x + 2)

    limit (x ->2) - 5(x - 2)(x +1) / (x -2)(x - 1)

    limit (x -> 2) - 5(x+1) / (x -1)
    x= 2 , limit = - 5(2+1) / (2 - 1)  =  -15

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