F(x)=(2x-3)^100 Tent. f'(x) ...
Matematika
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Pertanyaan
F(x)=(2x-3)^100
Tent. f'(x) ...
Tent. f'(x) ...
1 Jawaban
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1. Jawaban yourvin
Jika f(x) = y = (2x-3)^100
misal, u = 2x-3
du/dx = 2
y = u^100
dy/du = 100 u^99
maka, f'(x) = dy/dx = dy/du . du/dx
dy/dx = 100 u^99 . 2
dy/dx = 200 u^99
dy/dx = 200 (2x-3)^99
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