Matematika fungsi limit, saya minta tolong menjawabkan ini.........

LimiT

4][
lim [x-->~] (x² - 2x - 3)/(x - 3)
= lim [x-->~] (x + 1)(x - 3) / (x - 3)
= ~ + 1
= ~

5][
lim [x-->~] (-2x² + 5x - 3)/(x + 3)
= lim [x-->~] (-2x - 1)(x + 3) / (x + 3)
= -2(~) - 1
= -~