Matematika

Pertanyaan

2√6 + 4√3(√32 - √72) =

A. 6√6
B. 4√6
C. √6
D. -6√6
E. -8√6

1 Jawaban


  • [tex]2 \sqrt{6} + 4 \sqrt{3} ( \sqrt{32 } - \sqrt{72} ) \\ = 2 \sqrt{6} + 4 \sqrt{3} ( \sqrt{16 \times 2} - \sqrt{36 \times 2} ) \\ = 2 \sqrt{6} + 4 \sqrt{3} (4 \sqrt{2} - 6 \sqrt{2} ) \\ = 2 \sqrt{6 } + 4 \sqrt{3} ( - 2 \sqrt{2} ) \\ = 2 \sqrt{6} - 8 \sqrt{6} \\ = - 6 \sqrt{6} [/tex]
    jadi jawabannya D

    semoga membantu

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