diketahui deret aritmatika s4 : 17 s8 :58.hitunglah s25

S4 = 4/2 ( 2a + 3b )
17 = 2 ( 2a + 3b )
17 = 4a + 6a

S8 = 8/2 ( 2a + 7b )
58 = 4 ( 2a + 7b )
58 = 8a + 28b

4a + 6a = 17 (×2) 8a + 12b = 34
8a + 28b = 58 (×1) 8a + 28b = 58
———————— -
- 16b = -24
b = 24/16 = 3/2

4a + 6a = 17
4a + 6(3/2) = 17
4a + 9 = 17
4a = 17 - 9
4a = 8
a = 8/4
a = 2

S25 = 25/2 ( 2(2) + 24(3/2))
S25 = 25/2 ( 4 + 36 )
S25 = 25/2 ( 40 )
S25 = 500


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