sumbu simetri parabola y=kx^2 +(k-1)x+1 adalah x=3 maka nilai k=

PaaBoLa

y = kx² + (k - 1)x + 1
a = k
b = k - 1
c = 1

Sumbu simetri = x = -b/2a
x = 3
-(k - 1)/(2 . k) = 1
-(k - 1) = 2k
-k + 1 = 2k
-k - 2k = -1
-3k = -1
k = 1/3