3 buah hambatan besarnya masing masing 2ohm,4ohm,12ohm disusun paralel berapakah hambatan penggantinya?

[tex] \frac{1}{r} = \frac{1}{2} + \frac{1}{4} + \frac{1}{12} \\ \frac{1}{r} = \frac{6 + 3 + 1}{12 } \\ \frac{1}{r} = \frac{10}{12} \\ r = \frac{12}{10} = 1.2 \: ohm[/tex]