Carilah akar akar tiap persamaan 2ײ+7×+2=0

2ײ+7×+2=0 ↝a = 2, b = 7, c = 2
x1,2 = -b ± (√(b²- 4ac))/2a
x1,2 = -7 ± (√(7²- 4.2.2))/2.2
x1,2 = -7 ± (√33/4)
x1 = -7 + (√33/4) atau
x2 = -7 - (√33/4)

semoga membantu ^^